Leave it to a PSU DUS (dumb, ugly, stupid) grad to omit critical details such as ……segment/leg length.Unpossible.
Leave it to a PSU DUS (dumb, ugly, stupid) grad to omit critical details such as ……segment/leg length.
We could be talking about five angles that could close to a quasi-pentagon on an page of letter paper or something much larger.
Five unequal sides:
426
500
242
213
600
Got no more. Read I have to make a triangle or somethingNeed another measurement.
Yep.Divide into a triangle and a trapezoid, find the area of each ad add them together.Got no more. Read I have to make a triangle or something
Did you just wake up? 2^4? Shouldn't it have been 2^2? But the rest of the logic seems to be correct.I’m actually not quite sure. When you know the sides of a triangle, it fixes the angles of the triangle so you can then find the area of the triangle by using Heron’s formula. In other words, two triangles with congruent sides are congruent copies of each other, so the areas are identical. This is not true with four-sided figures. You can’t say that every quadrilateral with sides 2 units has area 2^4 = 16 because this is true only if it’s a square; if it’s a non-square rhombus then the area will be less than 16. (Think about it: by tilting the rhombus you can make the area as small as you like.) There is zero reason to think that the same issue doesn’t happen with five-sided figures. It’s likely that you can have two different five-sided figures with identical sides and different areas. I’ve never thought about this before.
https://en.m.wikipedia.org/wiki/Heron's_formula
Schooled. Yes, I just woke up and just spit out my coffee. It’s not the first time Herbie has schooled me, won’t be the last. I edited my original post but you can see my mistake in Herbie’s post.Did you just wake up? 2^4? Shouldn't it have been 2^2? But the rest of the logic seems to be correct.
You can have two different five-sided figures with identical sides and different areas. Think about a house, an equilateral triangle on top of a square. Now tilt the square one degree: this is a non-square rhombus with area less than that of the original square. Put the same equilateral triangle (same area as the original) on top of the new rhombus and you’ve got a new five-sided polygon with sides of identical length, with area different than that of the original.I’m actually not quite sure. When you know the sides of a triangle, it fixes the angles of the triangle so you can then find the area of the triangle by using Heron’s formula. In other words, two triangles with congruent sides are congruent copies of each other, so the areas are identical. This is not true with four-sided figures. You can’t say that every quadrilateral with each side 2 units has area 2^2 = 4 because this is true only if it’s a square; if it’s a non-square rhombus then the area will be less than 4. (Think about it: by tilting the rhombus you can make the area as small as you like.) There is zero reason to think that the same issue doesn’t happen with five-sided figures. It’s likely that you can have two different five-sided figures with identical sides and different areas. I’ve never thought about this before.
https://en.m.wikipedia.org/wiki/Heron's_formula
We are going to have to talk to you about your tenure in this organization. Come down to HR. And bring your company issued slide rule.Schooled. Yes, I just woke up and just spit out my coffee. It’s not the first time Herbie has schooled me, won’t be the last. I edited my original post but you can see my mistake in Herbie’s post.
Schooled. Yes, I just woke up and just spit out my coffee. It’s not the first time Herbie has schooled me, won’t be the last. I edited my original post but you can see my mistake in Herbie’s post.
I am sure it is all just a misunderstanding.That was your chance to say something like:
”Actually, Herb, I am correct. I am using Bogosian higher-order, dual-vector math to account for complex geometric variability inherent to incongruous two-dimensional shapes.”
We would be like, “Well, yeah. Sounds good.”
I’ve never once been able to BS Herb and know better than to try.That was your chance to say something like:
”Actually, Herb, I am correct. I am using Bogosian higher-order, dual-vector math to account for complex geometric variability inherent to incongruous two-dimensional shapes.”
We would be like, “Well, yeah. Sounds good.”
In addition to the rest of the incomplete information which makes the question impossible to answer, we need to know if the angles are convex or concave. Consider your rendering. If the angle on the right was concave, the circumference would be the same but the area would be reduced by what's between the convex and concave angles.easy peasy.... although you didn't tell us units of your numbersView attachment 187085
I did change the order of the side lengths up a few times....and as LionJim said, you DO get different values for the area
View attachment 187092View attachment 187093
ok run it so with the given perimeters, you maximize the areaIn addition to the rest of the incomplete information which makes the question impossible to answer, we need to know if the angles are convex or concave. Consider your rendering. If the angle on the right was concave, the circumference would be the same but the area would be reduced by what's between the convex and concave angles.
Yeah...you can keep the only parameters we were given and rearrange to get drastically different resultsIn addition to the rest of the incomplete information which makes the question impossible to answer, we need to know if the angles are convex or concave. Consider your rendering. If the angle on the right was concave, the circumference would be the same but the area would be reduced by what's between the convex and concave angles.
thats what a UK education is good forC'mon guys, lets keep things simple. I took today off and don't need the frustration of little Euclid's in my bowels causing constipation.
Two part question....
1) Approximate minutes for each man to experience a peak spasm finish
2) Any minutemen on the B&W up to the task?.....
This is Lisa Sparks, she holds the world record for "Most Partners in One Day". The woman had sex with 919 men in a single day. The previous record was held by Candy Apples, with 742 partners.
Lisa is a Master of Arts and Multimedia, graduated from the University of Kentucky, but was convinced by her husband to enter the adult film industry, where she became known by her stage name Lisa Sparkxxx.
I cannot think of a more ignominious record.C'mon guys, lets keep things simple. I took today off and don't need the frustration of little Euclid's in my bowels causing constipation.
Two part question....
1) Approximate minutes for each man to experience a peak spasm finish
2) Any minutemen on the B&W up to the task?.....
This is Lisa Sparks, she holds the world record for "Most Partners in One Day". The woman had sex with 919 men in a single day. The previous record was held by Candy Apples, with 742 partners.
Lisa is a Master of Arts and Multimedia, graduated from the University of Kentucky, but was convinced by her husband to enter the adult film industry, where she became known by her stage name Lisa Sparkxxx.
What about being guy 919?I cannot think of a more ignominious record.
I cannot think of a more ignominious record.
Lisa graduated from the University of Kentucky, but was convinced by her husband to enter the adult film industry
I don't believe it's true, one would have to be insane to be involved with this type of behavior.I cannot think of a more ignominious record.
What about being guy 919?
C'mon guys, lets keep things simple. I took today off and don't need the frustration of little Euclid's in my bowels causing constipation.
Two part question....
1) Approximate minutes for each man to experience a peak spasm finish
2) Any minutemen on the B&W up to the task?.....
This is Lisa Sparks, she holds the world record for "Most Partners in One Day". The woman had sex with 919 men in a single day. The previous record was held by Candy Apples, with 742 partners.
Lisa is a Master of Arts and Multimedia, graduated from the University of Kentucky, but was convinced by her husband to enter the adult film industry, where she became known by her stage name Lisa Sparkxxx.