We have a big game on Thursday (1/9/25). What are you doing to prepare?

Bkmtnittany1

Well-known member
Oct 26, 2021
4,545
7,064
113
fire grilling GIF by Grillax®
Holy sh*t!
 
  • Like
Reactions: BobPSU92 and Bwifan

Bkmtnittany1

Well-known member
Oct 26, 2021
4,545
7,064
113
It would be nice to have a few pints and scan thru the Weather thread… but Tom screwed us!!
 

PSU Mike

Well-known member
Oct 6, 2021
2,408
3,983
113
More specifically, it can be a direct sum of copies of Z_2. In particular, we have to have x+x=0 always. Here’s why. If x^2=x then 1+x=(1+x)^2=1+2x+x^2=1+2x+x and you cancel out 1+x from both sides, get 0=2x. You also have x(1+x)=x+x^2=x+x=0, so you have a whole bunch of zero divisors and only one unit, 1. In the first sentence I said it can be a direct sum of copies of Z_2, and I’m trying to figure out if this is always the case. If the ring is finite I am positive that it has to be the case (I need a proof) but what if it’s infinite? I’m not trying to be a show off here, it’s just that I find this stuff gloriously fascinating.
Ring, or mental circle jerk?
 

Bkmtnittany1

Well-known member
Oct 26, 2021
4,545
7,064
113
I’m balancing workouts with rest and am also hitting the carbs hard at the training table. Otherwise, I’m watching a lot of nd game film and feel confident with what I want to do on offense and defense. To be clear, I will go both ways on Thursday night.

You?

I could talk about nipples in the context of algebraic topology, would that work for you?
Pics please!
 
  • Haha
Reactions: LionJim

PSU1969A

Active member
Nov 3, 2021
245
321
63
More specifically, it can be a direct sum of copies of Z_2. In particular, we have to have x+x=0 always. Here’s why. If x^2=x then 1+x=(1+x)^2=1+2x+x^2=1+2x+x and you cancel out 1+x from both sides, get 0=2x. You also have x(1+x)=x+x^2=x+x=0, so you have a whole bunch of zero divisors and only one unit, 1. In the first sentence I said it can be a direct sum of copies of Z_2, and I’m trying to figure out if this is always the case. If the ring is finite I am positive that it has to be the case (I need a proof) but what if it’s infinite? I’m not trying to be a show off here, it’s just that I find this stuff gloriously fascinating.
x^2=x
x^2 - x = 0
x(x-1) =0

x=0 or x=1

If one of my students gave me that supposed proof, I give them a ZERO>
 
  • Like
Reactions: Bison13

LionJim

Well-known member
Oct 12, 2021
11,023
15,146
113
x^2=x
x^2 - x = 0
x(x-1) =0

x=0 or x=1

If one of my students gave me that supposed proof, I give them a ZERO>
This is true for the real numbers. The real numbers are a field (you can cancel) so anytime you multiply two numbers to get zero, one of them has to be zero. This isn’t true in general rings. As a simple example of this, suppose that you’re working in ZxZ, which is a ring consisting of all ordered pairs (x,y) where x and y are integers. Simple idea, you have elements like (3,2) and (-4,7) and you multiply and add component wise so that (5,7)+(4,2)=(9,9) and (2,3)(5,4)=(10,12). So you have (0,5)(2,0)=(0,0), the zero element in ZxZ, you have two non-zero elements multiplying to the zero element. Same thing with, say, Z_6. When you divide a number by 6, you get a reminder, right, and this reminder will be 0,1,2,3,4,5, right? So you just focus on the remainders and do the math from there. So you get 2+3=5 and 5+2=1 because 5+2=7 and when you divide 7 by 6 your remainder is 1. In the same way you get 2x5=4 (because the remainder you get when you divide 10 by 6 is 4) and 3x5=3 (because the remainder you get when you divide 15 by 6 is 3). In particular you have 3=3x5=3x1, and you cannot cancel the 3. Same way, you get 3x4=0 (because 3x4=12 and 12 is evenly divided by 6, the remainder is 0). You have two non-zero elements multiplying to zero. What you wrote is true in a field. The ring of real numbers is a field. Boolean rings are, in general, not fields.

 
Last edited:
  • Like
Reactions: Bison13

LionJim

Well-known member
Oct 12, 2021
11,023
15,146
113
This is true only for the real numbers. The real numbers are a field (you can cancel) so anytime you multiply two numbers to get zero, one of them has to be zero. This isn’t true in general rings. As a simple example of this, suppose that you’re working in ZxZ, which is a ring consisting of all ordered pairs (x,y) where x and y are integers. Simple idea, you have elements like (3,2) and (-4,7) and you multiply and add component wise so that (5,7)+(4,2)=(9,9) and (2,3)(5,4)=(10,12). So you have (0,5)(2,0)=(0,0), the zero element in ZxZ, you have two non-zero elements multiplying to the zero element. Same thing with, say, Z_6. When you divide a number by 6, you get a reminder, right, and this reminder will be 0,1,2,3,4,5, right? So you just focus on the remainders and do the math from there. So you get 2+3=5 and 5+2=1 because 5+2=7 and when you divide 7 by 6 your remainder is 1. In the same way you get 2x5=4 (because the remainder you get when you divide 10 by 6 is 4) and 3x5=3 (because the remainder you get when you divide 15 by 6 is 3). In particular you have 3=3x5=3x1, and you cannot cancel the 3. Same way, you get 3x4=0 (because 3x4=12 and 12 is evenly divided by 6, the remainder is 0). You have two non-zero elements multiplying to zero. What you wrote is true in a field. The ring of real numbers is a field. Boolean rings are, in general, not fields.

If you’re working in ZxZxZxZ, then
(1,1,0,1), (0,1,1,0) (1,1,1,1), and (0,0,0,0) are each solutions to x^2=x. In this case you would have precisely sixteen different solutions to x^2=x. In Boolean rings you can refine it even more so that every x is a solution to x^2=x. I would say that this is second year graduate level algebra.
 
Last edited:

ODShowtime

Well-known member
Nov 1, 2021
2,708
5,528
113
Lock the f— in, or LTFI for short, has become a theme for Penn State’s Playoff run. It embodies Franklin’s 1-0 mantra but with a less corny and more edgy delivery. LTFI has become a hashtag used by Penn State fans on social media when mentioning the next game. Like their head coach, they’re not looking past any opponent. It’s also a message that’s been printed on merchandise with Penn State’s NIL collective, Happy Valley United.---Audrey Snyder The Athletic

The bottom line, that everyone needs to understand, is this. We win one more game and we're in the National Championship game. We win two games and we're National Champions.

That's it.

Win Two Games
 

BostonNit

Well-known member
Oct 27, 2021
849
1,720
93
Just finished packing for a little trip to Miami. I hope I can find something interesting to do Thursday evening.
 
  • Like
Reactions: rudedude

MtNittany

Well-known member
Oct 12, 2021
1,666
2,241
113
Last game I had to get up at 5am the next day. It was tough. This one - free and clear. The Yueng drafts will flow. Cold down here. Thinking about a mini beef-wellington. Going to Doris' market tomorrow. We'll see what I come back with.
 

Erial_Lion

Well-known member
Nov 1, 2021
2,320
2,823
113
If you have an hour to kill in the next two days, this week's episode is definitely worth a listen. Tengwall should have a bright future in sports media. As I mentioned elsewhere, I was dying at Tengwall's Cam Rising story. And thinking about Mike the Mailman drinking at G-Man with a 22 year old Al Golden also cracks me up.

 
Last edited:
  • Like
Reactions: Zenophile

rudedude

Well-known member
Oct 6, 2021
6,756
13,458
113
More specifically, it can be a direct sum of copies of Z_2. In particular, we have to have x+x=0 always. Here’s why. If x^2=x then 1+x=(1+x)^2=1+2x+x^2=1+2x+x and you cancel out 1+x from both sides, get 0=2x. You also have x(1+x)=x+x^2=x+x=0, so you have a whole bunch of zero divisors and only one unit, 1. In the first sentence I said it can be a direct sum of copies of Z_2, and I’m trying to figure out if this is always the case. If the ring is finite I am positive that it has to be the case (I need a proof) but what if it’s infinite? I’m not trying to be a show off here, it’s just that I find this stuff gloriously fascinating.
Austin Powers Nerd GIF

😂😂😂😂😂 you da man LJ!
 

Marshall2323

Well-known member
Aug 7, 2024
853
1,399
93
I just scouted ND, not a single TD earned. We just dominated 2 with lane discipline. If we PUNISH 13 like we did 2, ND got nothing for us. I guarantee a lions win.
I just scouted ND, not a single TD earned. We just dominated 2 with lane discipline. If we PUNISH 13 like we did 2, ND got nothing for us. I guarantee a lions win.
I just scouted ND, not a single TD earned. We just dominated 2 with lane discipline. If we PUNISH 13 like we did 2, ND got nothing for us. I guarantee a lions win.
Your guarantee is the "kiss of death."
 

ApexLion

Well-known member
Nov 1, 2021
4,096
7,030
113
Additional things to do:

1) work out twice to relieve anxiety
2) watch copious amounts of film - mostly Woody Allen or Coppola
3) have a scone
4) apply face paint today as like a run thru - that will go over well with spouse I'm sure

I'll think of more later.